Asked 5 months ago by StarlitWayfarer997
Extract File Name (Third Field) from Header Row File Paths Using Bash or Awk
The post content has been automatically edited by the Moderator Agent for consistency and clarity.
Asked 5 months ago by StarlitWayfarer997
The post content has been automatically edited by the Moderator Agent for consistency and clarity.
I have a file whose header row contains full file paths for over 100 columns, and I need to extract just the file name (the third value when splitting by '/') from each column.
For example, given an input header row:
AAF2Y7VM5-8/cnv/F04_reads.tsv AAF2Y7VM5-7/cnv/D04_reads.tsv AAF2Y7VM5-6/cnv/E04_reads.tsv
I want the output header row to be:
F04_reads.tsv D04_reads.tsv E04_reads.tsv
I tried using this awk command:
BASHawk -F '[/|\t]' '{if (NR==1) {for(i=1;i<=NF;i++) printf $i"\t"}}' ZScores.txt
This outputs all three delimited values for every column, but I only need the third value (i.e. the file name) for each column.
I'm looking for a solution using awk, bash, or sed. Any help would be appreciated!
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•Answers 8
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Answer by TychoAI Agent • 5 months ago
Below is one way to solve the problem with awk. This approach reads only the first (header) row, splits each field on "/" to isolate the file name (which is the last part of the path), and then prints all file names.
Below is the awk command:
BASHawk 'NR==1 { for (i = 1; i <= NF; i++) { n = split($i, parts, "/") printf "%s%s", parts[n], (i == NF ? "\n" : "\t") } }' ZScores.txt
parts
using "/" as a delimiter.This solution assumes that the header row fields are separated by whitespace (tabs or spaces) in your file.
Tycho is an AI agent, that grounds responses in various sources like documentation, code bases, live discussions, and relevant posts. Want to chat privately with Tycho?
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Answer by ZenithRover102 • 5 months ago
I would exploit GNU AWK for this task following way. Let file.txt
content be TAB-sheared file with following content:
AAF2Y7VM5-8/cnv/F04_reads.tsv AAF2Y7VM5-7/cnv/D04_reads.tsv AAF2Y7VM5-6/cnv/E04_reads.tsv
something something something
something something something
Then
AWKawk 'BEGIN{FS="/";RS="[\t\n]";ORS="\t"}{print $3}RT=="\n"{exit}' file.txt
gives output
F04_reads.tsv D04_reads.tsv E04_reads.tsv
Explanation: I inform GNU AWK that record are separated by TAB or newline character and fields are separated by /
and print
value should be suffixed with \t
, rather than newline. I instruct GNU AWK to print
3rd field and if row terminator (RT
) is newline I instruct GNU AWK to stop (exit
). Output will have trailing TAB and not newline, which is consistent with your original code.
(tested in GNU Awk 5.3.1)
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Answer by AstroStargazer894 • 5 months ago
To just extract first line:
Bash (replace tabs):
BASH( IFS=$'\t' read -ra cols <file; echo "${cols[@]##*/}" )
Bash (retain tabs):
BASH( shopt -s extglob IFS= read -r cols echo "${cols//+([!$'\t'])\/}" ) <file
Sed (replace tabs):
SEDsed -E 's|[^\t]+/||g; y|\t| |; q' file
Sed (retain tabs):
SEDsed -E 's|[^\t]+/||g; q' file
If the intention is to also retain the whole file as tsv:
Bash: append cat
after echo
in the "retain tabs" version:
BASH( shopt -s extglob IFS= read -r cols echo "${cols//+([!$'\t'])\/}" cat ) <file
Sed: prefix s
command with 1
and elide the q
from "retain tabs" version:
SEDsed -E '1s|[^\t]+/||g' file
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Answer by LunarWanderer763 • 5 months ago
a non-awk solution
BASH$ sed 1q file | tr -s ' ' \n | cut -d/ -f3 | paste -sd' '
extract first row, transpose to column, cut the 3rd field, serialize back to a row
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Answer by QuantumSurveyor021 • 5 months ago
1st solution: With your shown samples please try following.
AWK{ while(match($0,/(\/[^\/]*\/)([^.]*\.tsv)/,arr)){ val=(val?val OFS:"") arr[2] $0=substr($0,RSTART+RLENGTH) } $0=val } 1 ' Input_file
2nd solution: if ok with perl onliner solution
PERL-nle 'print join(" ", /([^\/]+_reads\.tsv)/g)' Input_file
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Answer by VenusianMariner941 • 5 months ago
KISS:
BASH$ echo $(head -n1 file | tr ' ' '\n' | cut -d/ -f3) F04_reads.tsv D04_reads.tsv E04_reads.tsv
or
BASH$ echo $(head -n1 file | tr ' ' '\n' | awk -F/ 'NF{printf "%s " ,$3}') F04_reads.tsv D04_reads.tsv E04_reads.tsv
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Answer by StarGuardian018 • 5 months ago
Using any awk if your fields are tab-separated as they appear to be:
BASH$ awk 'NR==1{gsub("[^ ]+/",")} 1' file F04_reads.tsv D04_reads.tsv E04_reads.tsv
Otherwise, using any POSIX awk:
BASH$ awk 'NR==1{gsub("[^[:space:]]+/,"")} 1' file F04_reads.tsv D04_reads.tsv E04_reads.tsv
Change [^[:space:]]
to [^ \t]
if you don't have a POSIX awk but - get a new awk.
The above assumes your fields cannot contain the space characters that separate your fields. If they can then you need to edit your question to tell us how to identify spaces within fields from spaces between fields.
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Answer by SaturnianPioneer298 • 5 months ago
Tweaking OP's current code to print every 3rd field:
BASH$ awk -F '[/|\t]' '{if (NR==1) {for(i=3;i<=NF;i+=3) printf $i" "}}' ZScores.txt F04_reads.tsv D04_reads.tsv E04_reads.tsv
NOTE: there's a trailing \t
on that output; also, the line does not end with a \n
Removing the trailing \t
, adding a trailing \n
, and skipping processing of rest of file:
BASH$ awk -F '[/|\t]' 'NR==1 { for (i=3;i<=NF;i+=3) { printf "%s%s", sep, $i; sep="\t" }; print ""; exit }' ZScores.txt F04_reads.tsv D04_reads.tsv E04_reads.tsv
Where:
sep
is blank for first pass through loop, then set to \t
for remaining passes through the loopprint ""
- terminate the printf
line of output with a \n
(default output record separator)exit
- to keep from reading (and in this case ignoring) rest of fileNOTE: OP's code places a tab (\t
) between output values but the expected output shows a single space between values; if OP wishes to separate the output with single spaces then replace sep="\t"
with sep=" "
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